Skip to main content

Solids of Revolution Revisited

Introduction

In my previous blog post on solids of revolution, we looked at the object formed by rotating the area between \(f(x) = -\frac{1}{9}x^2+\frac{3}{4} \) and \( g(x)=\frac{1}{2}-\frac{1}{2}e^{-x} \) around the \( x \) axis and bounded by \( x = 0 \) and \( x = 1.5 \). When this solid is approximated using 10 washers, the resulting object looks like this:

When I was looking back over the 3D prints I’d created for this course, I noticed that the print for this example was the least interesting of the bunch. Looking at the print now, I feel like the shape is rather uninteresting. The curve I chose has such a gradual slope that each of the washers are fairly similar in size and causes the overall shape to just look like a cylinder. Since calculating the changes in the radiuses of the washers is a big part of the washer method, I don’t think this slowly decreasing curve was the best choice to illustrate the concept. The reason I had done this originally was because I hadn’t realized you could add supports to the print, and so I wanted to avoid printing anything that would have an overhang. Now that I have a lot more experience with 3D printing, I am going to alter this example to fix these issues.

A New Example

To revise my example, I want to change the outside curve to something that changes directions, which will make the outside of the object much more exciting. I don’t want to use any trigonometric curves that would be difficult to integrate, so instead I’ve decided to use the 3rd degree polynomial, \( f(x)=x^3-4x^2+4x+1 \).

I considered whether or not to change the function for the inner radius as well, which was also a fairly unexciting curve. Ultimately, I decided to keep the same equation (although I did need to scale it fit my new boundaries) because together the resulting solid of revolution looked like a flower vase. Something I’d really liked about my original item was that it looked like a real world object (I compared it to a piece of candy), so I wanted to make sure that my new object still had some sort of application. I want it to look interesting while still having the appearance of an everyday object- in this case, a flower vase.

As a result, I ended up using the following curves on the interval \( 0\le x\le2.5 \) for my new example:

The resulting print is shown below and is much more eye-catching than my original. I think that this change made the object a much better representation of the washer method as well. The washer method can calculate the volume of so many different solids, so I think it is much more fitting for it to be demonstrated through a less boring example.

Author: Sarah Bombrys

Comments

Popular posts from this blog

Finding an object's center of mass using integration

Thinking about center of mass As a kid, I would sit in class and balance my pencil on my finger. What I didn't know then was that I was finding the pencil's center of mass. An object's center of mass is a point where the average weight of the object lies. In other words, the weighted position vectors of the object at this point sum to zero (source: https://www.dictionary.com/browse/center-of-mass ). The exact location of this point can be found using calculus. First, it is important to understand the moment . The moment for a two-dimensional object is given with respect to both the x- and y-axes. It is a physical characteristic of the object a certain distance from these axes. It's easiest to think about the axes as reference points for where the characteristic acts; in this case, where the mass is distributed. When computing these moments, the hardest concept to grasp is that the moment with respect to y, for example, is given by the x-coordinat...

Do Over: Integration Over a Region in a Plane

Throughout the semester we have covered a variety of topics and how their mathematical orientation applies to real world scenarios. One topic we discussed, and I would like to revisit, is integration over a region in a plane which involves calculating a double integral. Integrating functions of two variables allows us to calculate the volume under the function in a 3D space. You can see a more in depth description and my previous example in my blog post, https://ukyma391.blogspot.com/2021/09/integration-for-over-regions-in-plane_27.html . I want to revisit this topic because in my previous attempt my volume calculations were incorrect, and my print lacked structural stability. I believed this print and calculation was the topic I could most improve on and wanted to give it another chance. What needed Improvement? The function used previously was f(x) = cos(xy) bounded on [-3,3] x [-1,3]. After solving for the estimated and actual volume, it was difficult to represent in a print...

Finding the Center of Mass of a Toy Boat

Consider two people who visit the gym a substantial amount. One is a girl who loves to lift weights and bench press as much as she possibly can. The other is a guy who focuses much more on his legs, trying to break the world record for squat weight. It just so happens that these two are the same height and have the exact same weight, but the center of their weight is not in the same part of their body. This is because the girl has much more weight in the top half of her body and the boy has more weight in the bottom half. This difference in center of mass is a direct result of the different distributions of mass throughout both of their bodies. Moments and Mass There are two main components to finding the center of mass of an object. The first, unsurprisingly, is the mass of the whole object. In this case of the boat example, the mass will be uniform throughout the entire object. This is ideal a majority of the time as it drastically reduces the difficulty...