Skip to main content

Level Curves

Chugging along through calculus topics, we find ourselves this week looking at the level curves of a surface. First we want to realize that when you take a function with two variables, you are graphing in the 3D world. For example, any function $f(x,y)$ would need to be graphed in 3D space. Now, level curves go hand in hand with this 3D space. Basically, we want to eliminate a variable, so we can graph this instead in the 2D plane. We do this by introducing a $ \ k \ $ such that $k = f(x,y)$, where $k$ is what the function equals at some $x$ and $y$. We then solve this equation for $y$ instead, thus having an equation with only one variable. Now, graphing this equation will give you some representation of the original 3D shape in the 2D world.

A Starting Example:

Let's talk about how this actually works. For simplicity sake, take the function $f(x,y) = x + y$. From our discussion, we want to say that this function equals some $k$, so $k = x + y$. Moreover, this then just says that $y = k - x$. By graphing this equation for different values of $k$, we basically sketch out how the original function would look like in the 2D world! Below you will find what the original function looks like in the 3D world, along with the level curves! In this example, I took $ -1 \leq k \leq 5$, so we can have some ideas as to what is happening!

Level Curves:


Plane in 3D Space:


Our Function For Exploring:

Have you ever been eating your tacos and wished you did not have to lay it down on your plate? Those square base taco shells can be expensive! So, what if we just made our own taco shell holder?! In honor of national Taco day, we will construct a taco stand! We will create this shape on the 3D plane and use level curves to see what it would look like in 2D! This function serves as a nice example as to what we are wanting to accomplish as well as having a tie to (what should be considered) a global holiday!

For our function, we have: $f(x,y) = 4\cos(20x) - 2\cos(80y)$! Going again by our previous discussions, we want to make this a function with a singular variable and just change the values for $k$! Now, how do we solve this for $k$? We have a good amount of algebra and trig ahead of us!

$k = 4\cos(20x) - 2\cos(80y)$
$2\cos(80y) = 4\cos(20x) - k$
$\cos(80y) = \frac{4\cos(20x) - k}{2}$
$80y = \cos^{-1}(\frac{4\cos(20x) - k}{2})$
$y = \frac{\cos^{-1}(\frac{4\cos(20x) - k}{2})}{80}$

Now we have this nice little function in terms of just the variable $x$ and the $k$ that we will assign different values to! In order to make sure we have enough to get a sense of what the object looks like and how it behaves, I will show for when $ -4 \leq k \leq 4$. Below you will find the graph of these level curves on the 2D plane!

Level Curves For Our Taco Holder:


Okay, this may be intimidating at first, but we just want to observe some important pieces of this graph. Firstly, we see that there are some open spaces between the valleys. Also, these valleys are not very steep, but rather close together. This is an excellent position to place a taco! We are not going to make it so the taco would be in-closed, because that would defeat the purpose! Below you will find what the 3D rendering of this shape is, where the lines along the edge are the level curves that we found! Also, I placed a holder on the bottom for either taco munching on the go or just for better balancing!

Our Taco Holder:


This example was picked for the specific reason of taking an ordinary object and seeing it as a graph or function instead! Since I am in STEM Education, these sort of examples are ideas I want to incorporate in my teaching and classrooms. For many students, math is a topic that they do not notice in their everyday lives just due to past teaching methods. By finding small examples like the taco holder, I hope to bridge those gaps between mathematical topics and the real world so they may see the beauty of math in their everyday lives!

Comments

Popular posts from this blog

Do Over: Integration Over a Region in a Plane

Throughout the semester we have covered a variety of topics and how their mathematical orientation applies to real world scenarios. One topic we discussed, and I would like to revisit, is integration over a region in a plane which involves calculating a double integral. Integrating functions of two variables allows us to calculate the volume under the function in a 3D space. You can see a more in depth description and my previous example in my blog post, https://ukyma391.blogspot.com/2021/09/integration-for-over-regions-in-plane_27.html . I want to revisit this topic because in my previous attempt my volume calculations were incorrect, and my print lacked structural stability. I believed this print and calculation was the topic I could most improve on and wanted to give it another chance. What needed Improvement? The function used previously was f(x) = cos(xy) bounded on [-3,3] x [-1,3]. After solving for the estimated and actual volume, it was difficult to represent in a print...

Knot 9-31

Knot 9-31 A knot is mathematics is defined as a closed, non-self-intersecting curve that is placed in three dimensions and cannot be the "unknot". The main difference between a knot in the real world and a known in mathematics is that a knot in mathematics does not contain any extra strands. The example following will help visualize this. Today, I have specifically chosen knot 9-31 from the Knot Atlas. This knot is very unique and contains some very interesting properties that we are going to look into. The Crossing Number For my knot today, I chose knot 9-31 from the Knot Atlas. This knot contains 9 crossings! The Unknotting Number The unknotting number is exactly what is sounds like. This is the minimum number of times the knot must be passed through itself to untie it. Luckily, the Knot Atlas is super useful and provides the unknotting number for us, but I still...

Do Over: Integration for Over Regions in the Plane

Introduction Earlier in the semester, we visited the topic of integration for over region regions in the plane. This was our first experience with taking integration in the third dimension. To do this, we had to use double integrals to calculate the volume of a region between two surfaces. This topic seems relatively straightforward and anyone who has taken a higher calculus class knows of double integrals. Today, we are going to revisit this topic for a couple of reasons. Why Double Integrals Again? As mentioned before, I am revisiting this topic for a couple of reasons. One of the main reasons is due to how the 3D print turned out. Due to the function, I chose, the final rectangular prism was stand alone. When printing, this resulted in a sloppy prism that lacked structural integrity. The image below is a reference to my original design that includes the prism that had the issue. The main cause of ...